#include <iostream> #include <algorithm> #include <cstring> using namespace std; const int N = 1e4 + 10; int n, m; int w[N]; int main() { scanf("%d%d", &n, &m); for(int i = 1; i <= n; i ++ ) scanf("%d", &w[i]); while(m -- ) { int k = n; while(w[k - 1] > w[k]) k -- ; int t = k; while(w[t + 1] > w[k - 1]) t ++ ; swap(w[k - 1], w[t]); reverse(w + k, w + n + 1); } for(int i = 1; i <= n; i ++ ) printf("%d ", w[i]); return 0; } 作者:Once. 链接:https://www.acwing.com/activity/content/code/content/3396797/ 来源:AcWing 著作权归作者所有。商业转载请联系作者获得授权,非商业转载请注明出处。
next_permutation写法
#include <iostream> #include <algorithm> #include <cstring> using namespace std; const int N = 1e4 + 10; int n, m; int w[N]; int main() { scanf("%d%d", &n, &m); for(int i = 1; i <= n; i ++ ) scanf("%d", &w[i]); while(m -- ) { next_permutation(w + 1, w + n + 1); } for(int i = 1; i <= n; i ++ ) printf("%d ", w[i]); return 0; } 作者:Once. 链接:https://www.acwing.com/activity/content/code/content/3396797/ 来源:AcWing 著作权归作者所有。商业转载请联系作者获得授权,非商业转载请注明出处。