C/C++教程
链表C/C++实现大全
本文主要是介绍链表C/C++实现大全，对大家解决编程问题具有一定的参考价值，需要的程序猿们随着小编来一起学习吧！
#include <iostream>
#include <stdio.h>
#include <string.h>
#include <conio.h>
using namespace std;
typedef struct student
{
int data;
struct student *next;
}node;
/* 链表的创建*/
node *creat()
{
node *head,*p,*s;
int x;
int cycle=1;
head=(node*)malloc(sizeof(node));
p=head;
while(cycle)
{
cout<<"please enter a number"<<endl;
cin>>x;
if(x!=0)
{
s=(node*)malloc(sizeof(node));
s->data=x;
p->next=s;
p=s;
}
else
cycle=0;
}
head=head->next;
p->next=NULL;
return (head);
}
/*链表的测长*/
int length(node *head)
{
int n=0;
node *p;
p=head;
while(p!=NULL)
{
p=p->next;
n++;
}
return n;
}
/*链表的排序*/
node *sort(node* head, int n)
{
int i;
int j;
int temp;
node *p;
if(head==NULL||head->next==NULL)
return (head);
p=head;
for(i=1;i<n;i++)
{
p=head;
for(j=0;j<n-i;j++)
{
if(p->data>p->next->data)
{
temp=p->next->data;
p->next->data=p->data;
p->data=temp;
}
p=p->next;
}
}
return (head);
}
/*链表的逆置*/
node *reverse(node* head)
{
node *p1;
node *p2;
node *p3;
if(head==NULL||head->next==NULL)
return head;
p1=head;
p2=p1->next;
while(p2)
{
p3=p2->next;
p2->next=p1;
p1=p2;
p2=p3;
}
head->next=NULL;
head=p1;
return head;
}
/*链表插入一个节点*/
node *insert(node* head,int num)
{
node *p0,*p1,*p2;
p1=head;
p0=(node*)malloc(sizeof(node));
p0->data=num;
while((p0->data)>(p1->data)&&p1->next!=NULL)
{
p2=p1;
p1=p1->next;
}
if(p0->data<=p1->data)
{
if(head==p1) //插入的是头结点
{
p0->next=p1;
head=p0;
}
else
{
p2->next=p0; //插入的是中间结点
p0->next=p1;
}
}
else //插入的是尾结点
{
p1->next=p0;
p0->next=NULL;
}
return (head);
}
/*链表删除一个节点*/
node *del(node* head,int num)
{
node *p1,*p2;
p1=head;
while(num!=p1->data&&p1->next!=NULL)
{
p2=p1;
p1=p1->next;
}
if(num==p1->data)
{
if(head==p1)
{
head=p1->next;
free(p1);
}
else
p2->next=p1->next;
}
else
cout<<num<<"couldn't be found"<<endl;
return (head);
}
void main()
{
node *p;
node *head;
int n;
head=(node*)malloc(sizeof(node));
head=creat();
n=length(head);
p=head;
cout<<"原始链表是：";
if(head!=NULL) //原始链表的打印
while(p!=NULL)
{
cout<<p->data<<" ";
p=p->next;
}
cout<<endl;
head=reverse(head);
p=head;
cout<<"链表长度为："<<n;
/**************************************************************/
cout<<"逆置后链表是：";
if(head!=NULL) //逆置后链表的打印
while(p!=NULL)
{
cout<<p->data<<" ";
p=p->next;
}
cout<<endl;
/**************************************************************/
head=sort(head,n);
p=head;
cout<<"排序后链表：";
if(head!=NULL) //排序后链表的打印
while(p!=NULL)
{
cout<<p->data<<" ";
p=p->next;
}
cout<<endl;
/**************************************************************/
int a;
cout<<"insert a number:"<<endl;
cin>>a;
head=insert(head,a);
p=head;
cout<<"插入后链表是：";
if(head!=NULL) //插入后链表的打印
while(p!=NULL)
{
cout<<p->data<<" ";
p=p->next;
}
cout<<endl;
/**************************************************************/
int b;
cout<<"delete number:"<<endl;
cin>>b;
head=del(head,b);
p=head;
cout<<"删除后链表是：";
if(head!=NULL) //删除后链表的打印
while(p!=NULL)
{
cout<<p->data<<" ";
p=p->next;
}
cout<<endl;
}
我自己完全用C语言版本的实现：
list.h
typedef struct ListNode
{
int val;
struct ListNode *next;
} Node;
Node *list_init(void); //构建头节点head值为-1的单链表
void list_exit(Node **head);
int list_is_empty(Node *head);
void list_print(Node *head);
int list_size(Node *head);
Node *list_insert(Node *head, int n, int val); //在第n个节点之后插入
int list_delete(Node *head, int n); //删除第n个节点
int list_delete_val(Node *head, int val); //删除链表中值为val的第一个节点
int list_find(Node *head, int val); //查找链表中第一个节点值为val的节点位置
Node *list_local_reverse(Node *head, int L, int R); //局部反转链表第L个到第R个节点
Node *list_reverse(Node *head); //链表反转
list.c
#include <stdio.h>
#include <stdlib.h>
#include "list.h"
int main(void)
{
Node *head = list_init();
list_print(head);
printf("list size = %d\n", list_size(head));
list_insert(head, 0, 5);
list_print(head);
printf("list size = %d\n", list_size(head));
list_insert(head, list_size(head), 15);
list_print(head);
printf("list size = %d\n", list_size(head));
list_reverse(head);
list_print(head);
printf("list size = %d\n", list_size(head));
list_delete(head, 1);
list_print(head);
list_delete(head, list_size(head));
list_print(head);
list_delete(head, 3);
list_print(head);
printf("list size = %d\n", list_size(head));
printf("find -1 in = %d\n", list_find(head, -1));
printf("find 5 in = %d\n", list_find(head, 5));
list_local_reverse(head, 1, 3);
list_print(head);
printf("list size = %d\n", list_size(head));
list_deinit(&head);
list_print(head);
list_size(head);
printf("list size = %d\n", list_size(head));
return 0;
}
Node *list_init(void)
{
Node *head = (Node *)malloc(sizeof(Node));
Node *p1 = (Node *)malloc(sizeof(Node));
Node *p2 = (Node *)malloc(sizeof(Node));
Node *p3 = (Node *)malloc(sizeof(Node));
Node *p4 = (Node *)malloc(sizeof(Node));
Node *p5 = (Node *)malloc(sizeof(Node));
head->val = -1;
p1->val = 11;
p2->val = 5;
p3->val = 7;
p4->val = 10;
p5->val = 1;
head->next = p1;
p1->next = p2;
p2->next = p3;
p3->next = p4;
p4->next = p5;
p5->next = NULL;
return head;
}
void list_exit(Node **head)
{
while (*head)
{
Node** tmp = head;
*head = (*head)->next;
free(*tmp);
*tmp = NULL;
}
}
int list_is_empty(Node *head){
return (!head || !head->next) ? 1 : 0;
}
void list_print(Node *head)
{
int first = 1;
while (head)
{
if (first)
{
first = 0;
printf("head->");
}
else
{
printf("(%d)->", head->val);
}
head = head->next;
}
printf("NULL\n");
}
int list_size(Node *head)
{
int len = 0;
if (!head)
return len;
head = head->next;
while (head)
{
len++;
head = head->next;
}
return len;
}
Node *list_insert(Node *head, int n, int val)
{
if (n < 0 || n > list_size(head))
return NULL;
while (n--)
{
head = head->next;
}
Node *tmp = (Node *)malloc(sizeof(Node *));
tmp->val = val;
tmp->next = head->next;
head->next = tmp;
return tmp;
}
int list_delete(Node *head, int n)
{
if (n < 1 || n > list_size(head))
return -1;
while (--n)
{
head = head->next;
}
Node *tmp = head->next;
head->next = head->next->next;
free(tmp);
tmp = NULL;
return 0;
}
int list_delete_val(Node *head, int val)
{
list_delete(head, list_find(head, val));
}
int list_find(Node *head, int val)
{
head = head->next;
int ans = 1;
while (head)
{
if (head->val == val)
return ans;
head = head->next;
ans++;
}
return -1;
}
Node *list_local_reverse(Node *head, int L, int R)
{
if (!head || !head->next || R <= L || L < 1 || R > list_size(head))
return NULL;
int t = L;
while (--t){
head = head->next;
}
Node *h = head;
head = head->next;
Node *p = head;
Node *q = head->next;
Node *tmp = NULL;
p->next = NULL;
int flag = 1;
while (flag != R - L + 1)
{
tmp = q->next;
q->next = p;
p = q;
q = tmp;
flag++;
}
h->next->next = tmp;
h->next = p;
return h;
}
Node *list_reverse(Node *head){
return list_local_reverse(head, 1, list_size(head));
}
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