注意、非回文数反转时，首数字有可能是0，输出字符串格式即可

注意、对字符串遍历时，可以不用考虑字符串长度时偶数还是奇数，用字符串长度除以2取整即可得到遍历查找对比的次数

注意、灵活使用for...else语句，区别break和exit()的区别

n = input()
for i in range(10):
    l = len(n)
    w = int(l/2)
    for k in range(w):
        if n[k] == n[l-1-k]:
            pass
        else:
            break
    else:
        print("%s is a palindromic number." % n)
        exit()
    m = n[::-1]
    s = int(n) + int(m)
    print("%s + %s = %d" % (n,m,s))
    n = str(s)
print("Not found in 10 iterations.")

判段字符串长度奇偶性，再遍历

n = input()
for i in range(10):
    l = len(n)
    if l % 2 == 0:          # 判断字符串长度是奇数还是偶数，方便后续循环查找比较
        w = int(l/2)
    else:
        w = int((l-1)/2)
    for k in range(w):
        if n[k] == n[l-1-k]:
            pass
        else:
            break
    else:
        print("%s is a palindromic number." % n)   # 找到了回文数，输出字符串并退出
        exit()
    m = n[::-1]
    s = int(n) + int(m)
    print("%s + %s = %d" % (n,m,s))
    n = str(s)
print("Not found in 10 iterations.")