1,稀疏数组的介绍

2,练习

3,编码

package array;

/*
稀疏数组 --------------- 数据结构
 */
public class Demo08 {
    public static void main(String[] args) {
//        创建一个二维数组；11*11   0：没有棋子   1：黑棋    2：白棋

        int[][] array1 = new int[11][11];
        array1[1][2] = 1;
        array1[2][3] = 2;
//        输出原始的数组 ；
        System.out.println("输出原始的数组");

        for (int[] ints : array1) {
            for (int anInt : ints) {
                System.out.print(anInt + "\t");
            }
            System.out.println();
        }

        System.out.println("======================");
//        转换为稀疏数组保存
//        获取有效值 的个数 ；
        int sum = 0;
        for (int i = 0; i < 11; i++) {
            for (int j = 0; j < 11; j++) {
                if (array1[i][j] != 0) {
                    sum++;

                }
            }
        }
        System.out.println("获取有效值 的个数" + sum);


//    创建一个稀疏数组
        int[][] array2 = new int[sum + 1][3];

        array2[0][0] = 11;
        array2[0][1] = 11;
        array2[0][2] = sum;

//      遍历 二维数组 ，将非0的值 ，存放到稀疏数组中
        int count = 0;
        for (int i = 0; i < array1.length; i++) {
            for (int j = 0; j < array1[i].length; j++) {
                if (array1[i][j] != 0) {
                    count++;
                    array2[count][0] = i;
                    array2[count][1] = j;
                    array2[count][2] = array1[i][j];

                }
            }
        }

//输出稀疏数组
        System.out.println("输出稀疏数组");
        for (int i = 0; i < array2.length; i++) {
            System.out.println(array2[i][0] + "\t"
                    + array2[i][1] + "\t"
                    + array2[i][2] + "\t");
        }

        System.out.println("====================");
        System.out.println("稀疏数组还原");

//        读取稀疏数组 的值
        int[][] array3 = new int[array2[0][0]][array2[0][1]];
//给其中的元素还原他的值
        for (int i = 1; i < array2.length; i++) {
            array3[array2[i][0]][array2[i][1]] = array2[i][2];
        }
//        打印
        for (int[] ints : array3) {
            for (int anInt : ints) {
                System.out.print(anInt + "\t");
            }
            System.out.println();
        }
    }
}

4,运行结果

输出原始的数组
0	0	0	0	0	0	0	0	0	0	0	
0	0	1	0	0	0	0	0	0	0	0	
0	0	0	2	0	0	0	0	0	0	0	
0	0	0	0	0	0	0	0	0	0	0	
0	0	0	0	0	0	0	0	0	0	0	
0	0	0	0	0	0	0	0	0	0	0	
0	0	0	0	0	0	0	0	0	0	0	
0	0	0	0	0	0	0	0	0	0	0	
0	0	0	0	0	0	0	0	0	0	0	
0	0	0	0	0	0	0	0	0	0	0	
0	0	0	0	0	0	0	0	0	0	0	
======================
获取有效值 的个数2
输出稀疏数组
11	11	2	
1	2	1	
2	3	2	
====================
稀疏数组还原
0	0	0	0	0	0	0	0	0	0	0	
0	0	1	0	0	0	0	0	0	0	0	
0	0	0	2	0	0	0	0	0	0	0	
0	0	0	0	0	0	0	0	0	0	0	
0	0	0	0	0	0	0	0	0	0	0	
0	0	0	0	0	0	0	0	0	0	0	
0	0	0	0	0	0	0	0	0	0	0	
0	0	0	0	0	0	0	0	0	0	0	
0	0	0	0	0	0	0	0	0	0	0	
0	0	0	0	0	0	0	0	0	0	0	
0	0	0	0	0	0	0	0	0	0	0	

Process finished with exit code 0