本文主要是介绍非递归遍历二叉树Java,对大家解决编程问题具有一定的参考价值,需要的程序猿们随着小编来一起学习吧!
import java.util.*;
public class Test {
static class TreeNode {
int val;
TreeNode left;
TreeNode right;
public TreeNode(int val) {
this.val = val;
}
}
public static void main(String[] args) {
TreeNode treeNode1 = new TreeNode(1);
TreeNode treeNode2 = new TreeNode(2);
TreeNode treeNode3 = new TreeNode(3);
TreeNode treeNode4 = new TreeNode(4);
TreeNode treeNode5 = new TreeNode(5);
TreeNode treeNode6 = new TreeNode(6);
TreeNode treeNode7 = new TreeNode(7);
treeNode1.left = treeNode2;
treeNode1.right = treeNode3;
treeNode2.left = treeNode4;
treeNode2.right = treeNode5;
treeNode3.left = treeNode6;
treeNode3.right = treeNode7;
List<Integer> f = in(treeNode1);
System.out.println(f);
System.out.println(pre(treeNode1));
System.out.println(post(treeNode1));
}
/**
* 中序遍历 非递归
*/
public static List<Integer> in(TreeNode root) {
List<Integer> res = new ArrayList<Integer>();
Stack<TreeNode> stk = new Stack<TreeNode>();
TreeNode p = root;
while (p != null || !stk.isEmpty()) {
while (p != null) {
stk.push(p);
p = p.left;
}
p = stk.pop();
res.add(p.val);
p = p.right;
}
return res;
}
/**
* 非递归先序
*/
public static List<Integer> pre(TreeNode root) {
List<Integer> res = new ArrayList<Integer>();
Stack<TreeNode> stk = new Stack<TreeNode>();
stk.push(root);
TreeNode p = root;
while (!stk.isEmpty()) {
p = stk.pop();
res.add(p.val);
if (p.right != null) {
stk.push(p.right);
}
if (p.left != null) {
stk.push(p.left);
}
}
return res;
}
/**
* 非递归后续遍历
*/
public static List<Integer> post(TreeNode root) {
List<Integer> res = new ArrayList<Integer>();
Stack<TreeNode> stk = new Stack<TreeNode>();
TreeNode p = root;
TreeNode prev = null;
while (p != null || !stk.isEmpty()) {
while (p != null) {
stk.push(p);
p = p.left;
}
p = stk.pop();
if (p.right == null || p.right == prev) {
res.add(p.val);
prev = p;
p = null;
} else {
stk.push(p);
p = p.right;
}
}
return res;
}
}
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