Java教程
实验五
本文主要是介绍实验五，对大家解决编程问题具有一定的参考价值，需要的程序猿们随着小编来一起学习吧！
task1-1
1 #include <stdio.h>
2 #define N 5
3 #define M 80
4 typedef struct
5 {
6 char name[M];
7 char author[M];
8 }Book;
9 int main()
10 {
11 Book x[N] = { {"一九八四", "乔治.奥威尔"},
12 {"美丽新世界", "赫胥黎"},
13 {"昨日的世界", "斯蒂芬.茨威格"},
14 {"万历十五年", "黄仁宇"},
15 {"一只特立独行的猪", "王小波"}
16 };
17 int i;
18 FILE *fp;
19 fp = fopen("data1.txt", "w");
20 if(fp == NULL)
21 {
22 printf("fail to open file\n");
23 return 1;
24 }
25 for(i=0; i<N; ++i)
26 {
27 fprintf(fp, "%-20s %-20s\n", x[i].name, x[i].author);
28 printf("%-20s %-20s\n", x[i].name, x[i].author);
29 }
30 fclose(fp);
31 return 0;
32 }
1 #include<stdio.h>
2 #define N 5
3 #define M 80
4 typedef struct
5 {
6 char name[M];
7 char author[M];
8 }Book;
9 int main()
10 {
11 Book x[N];
12 int i;
13 FILE *fp;
14 fp = fopen("data1.txt", "r");
15 if(fp == NULL)
16 {
17 printf("fail to open file\n");
18 return 1;
19 }
20 for(i=0; i<N; ++i)
21 {
22 fscanf(fp, "%s %s\n", x[i].name, x[i].author);
23 printf("%-20s %-20s\n", x[i].name, x[i].author);
24 }
25 fclose(fp);
26 return 0;
27 }
x[i].name和x[i].author本身作为一个地址。
1 #include <stdio.h>
2 #define N 5
3 #define M 80
4 typedef struct
5 {
6 char name[M];
7 char author[M];
8 }Book;
9 int main()
10 {
11 Book x[N] = { {"一九八四", "乔治.奥威尔"},
12 {"美丽新世界", "赫胥黎"},
13 {"昨日的世界", "斯蒂芬.茨威格"},
14 {"万历十五年", "黄仁宇"},
15 {"一只特立独行的猪", "王小波"}
16 };
17 int i;
18 FILE *fp;
19 fp = fopen("data2.dat", "wb");
20 if(fp == NULL)
21 {
22 printf("fail to open file\n");
23 return 1;
24 }
25 fwrite(x, sizeof(Book), N, fp);
26 fclose(fp);
27 return 0;
28 }
1 #include <stdio.h>
2
3 #define N 5
4 #define M 80
5
6 typedef struct
7 {
8 char name[M];
9 char author[M];
10 }BOOK;
11
12 int main()
13 {
14 BOOK x[N];
15 int i;
16
17 FILE *fp;
18
19 fp=fopen("data2.dat","rb");
20
21 if(fp==NULL)
22 {
23 printf("fail to open file\n");
24 return 1;
25 }
26
27 fread(x,sizeof(BOOK),N,fp);
28
29 for(i=0;i<N;i++)
30 printf("%-20s %-20s\n",x[i].name,x[i].author);
31
32 fclose(fp);
33
34 return 0;
35 }
1.Yes
2.No
task3.c
1 #include <stdio.h>
2
3 int main()
4 {
5 FILE *fin,*fout;
6 char ch;
7
8 fin=fopen("data3_1.txt","r");
9
10 if(fin==NULL)
11 {
12 printf("fail to open data3_1.txt\n");
13 return 1;
14 }
15
16 fout=fopen("data3_2.txt","w");
17
18 if(fin==NULL)
19 {
20 printf("fail to open data3_2.txt\n");
21 return 1;
22 }
23
24 while(!feof(fin))
25 {
26 ch=fgetc(fin);
27
28 if(ch>='a'&&ch<='z')
29 ch-=32;
30
31 fputc(ch,fout);
32 }
33
34 fclose(fin);
35 fclose(fout);
36
37 return 0;
38 }
1 #include <stdio.h>
2 #include <string.h>
3 #include <stdlib.h>
4 #define N 10
5 typedef struct
6 {
7 long int id;
8 char name[20];
9 float objective; /*客观题得分*/
10 float subjective; /*操作题得分*/
11 float sum;
12 char level[10];
13 } STU; // 函数声明
14 void input(STU s[], int n);
15 void output(STU s[], int n);
16 void process(STU s[], int n);
17 int main()
18 {
19 STU stu[N];
20 printf("从文件读入%d个考生信息: 准考证号，姓名，客观题得分(<=40)，操作题得分 (<=60)\n", N);
21 input(stu, N);
22 printf("\n对考生信息进行处理: 计算总分，确定等级\n");
23 process(stu, N);
24 printf("\n打印考生完整信息, 并保存到文件中");
25 output(stu, N);
26 return 0;
27 }
28 void input(STU s[], int n)
29 {
30 int i;
31 FILE *fin;
32 fin = fopen("examinee.txt", "r");
33 if (fin == NULL)
34 {
35 printf("fail to open file\n");
36 exit(0);
37 }
38 while (!feof(fin))
39 {
40 for (i = 0; i < n; i++)
41 fscanf(fin, "%ld %s %f %f", &s[i].id, s[i].name, &s[i].objective, &s[i].subjective);
42 }
43 fclose(fin);
44 }
45 void output(STU s[], int n)
46 {
47 FILE *fout;
48 int i; // 输出到屏幕
49 printf("\n");
50 printf("准考证号\t姓名\t客观题得分\t操作题得分\t总分\t\t等级\n");
51 for (i = 0; i < n; i++)
52 printf("%ld\t\t%s\t%.2f\t\t%.2f\t\t%.2f\t\t%s\n", s[i].id, s[i].name, s[i].objective, s[i].subjective, s[i].sum, s[i].level); // 保存到文件
53 fout = fopen("result.txt", "w");
54 if (!fout)
55 {
56 printf("fail to open or create result.txt\n");
57 exit(0);
58 }
59 fprintf(fout, "准考证号\t\t姓名\t客观题得分\t操作题得分\t总分\t\t等级\n");
60 for (i = 0; i < n; i++)
61 fprintf(fout, "%ld\t\t%s\t%.2f\t\t%.2f\t\t%.2f\t\t%s\n", s[i].id, s[i].name, s[i].objective, s[i].subjective, s[i].sum, s[i].level);
62 fclose(fout);
63 }
64 void process(STU s[], int n)
65 {
66 int i,j,k;
67 STU temp;
68 for(i=0;i<n;i++)
69 s[i].sum=s[i].objective+s[i].subjective;
70 for(i=0;i<n;i++)
71 for(k=0;k<n-1-i;k++)
72 if(s[k].sum<s[k+1].sum)
73 {
74 temp=s[k];
75 s[k]=s[k+1];
76 s[k+1]=temp;
77 }
78 j=n/10;
79 for(i=0;i<j;i++)
80 strcpy(s[i].level,"优秀");
81 k=n/2;
82 for(i=j;i<k;i++)
83 strcpy(s[i].level,"合格");
84 for(i=k;i<n;i++)
85 strcpy(s[i].level,"不合格");
86
87 }
1 #include <stdio.h>
2 #include <stdlib.h>
3 #include <time.h>
4 #define N 81
5 #define M 5
6 typedef struct
7 {
8 long int id;
9 char name[20];
10 char banji[60];
11 }STU;
12 int main()
13 {
14 int i,j;
15 STU x[N],ran[M];
16 FILE *fin,*fout;
17 fin = fopen("list.txt","r");
18 if(fin == NULL)
19 {
20 printf("fail to open list.txt\n");
21 return 1;
22 }
23 for(i=1;i<=N;i++)
24 fscanf(fin, "%ld %s %s", &x[i].id, x[i].name, x[i].banji);
25 fclose(fin);
26 srand(time(0));
27 j = rand()%(80)+1;
28 for(i=0;i<M;i++)
29 {
30 ran[i] = x[j];
31 j = rand()%(80)+1;
32 }
33 fout = fopen("lucky.txt", "w");
34 if(fout == NULL)
35 {
36 printf("fail to open file\n");
37 return 1;
38 }
39 for(i=0;i<M;i++)
40 {
41 fprintf(fout, "%ld %s %s\n", ran[i].id, ran[i].name, ran[i].banji);
42 printf("%ld %s %s\n", ran[i].id, ran[i].name, ran[i].banji);
43 }
44 fclose(fout);
45 return 0;
46 }
这篇关于实验五的文章就介绍到这儿，希望我们推荐的文章对大家有所帮助，也希望大家多多支持为之网！
您可能喜欢
-
ShardingSphere 如何完美驾驭分布式事务与 XA 协议？11-16
-
ShardingSphere如何轻松驾驭Seata柔性分布式事务？11-16
-
Maven资料入门指南11-16
-
Maven资料入门教程11-16
-
MyBatis Plus资料：新手入门教程与实践指南11-16
-
MyBatis-Plus资料入门教程：快速上手指南11-16
-
Mybatis资料入门教程：新手必看指南11-16
-
MyBatis资料详解：新手入门与初级实战指南11-16
-
MyBatisPlus资料：初学者入门指南与实用教程11-16
-
MybatisPlus资料详解：初学者入门指南11-16
-
MyBatisX资料：新手入门与初级教程11-16
-
RESTful接口资料详解：新手入门指南11-16
-
RESTful接口资料详解：新手入门教程11-16
-
Spring Boot资料：新手入门与初级教程11-16
-
Springboot资料：新手入门与初级教程11-16
栏目导航
