格式化双层数组使得时间复杂度为O(n)的尝试

1. 提取关键数据，将双层数组扁平化为单层
2. 单层再做转换

const infos = [
    {
        time: '2022-02-21',
        data: [{
            Duration: 22,
            Spec: "h264"
        },
        {
            Duration: 33,
            Spec: "h265_hd"
        },
        {
            Duration: 44,
            Spec: "h264_4k"
        }]
    },
    {
        time: '2022-02-22',
        data: [{
            Duration: 55,
            Spec: "h264"
        },
        {
            Duration: 66,
            Spec: "h265_hd"
        },
        {
            Duration: 77,
            Spec: "h264_4k"
        }]
    }
]

const _map = list => list
    .reduce((prev, cur) => prev.data.concat(cur.data))
    .reduce((total, { Duration, Spec }) => Object.assign(total, { [Spec]: (total[Spec] || []).concat(Duration) }), {})
const _list = map => Object.entries(map).map(([name, data]) => ({ name, data }))
_list(_map(infos))