Java教程
Tetris DFS算法练习
本文主要是介绍Tetris DFS算法练习，对大家解决编程问题具有一定的参考价值，需要的程序猿们随着小编来一起学习吧！
Tetris DFS算法练习
题目和分析有空再整理
package tetris;
/**
* @Author jinjun99
* @Date Created in 2021/11/22 16:46
* @Description
* @Since version-1.0
*/
public class Block {
/**
* 状态，0为普通块，1为特殊块。
*/
int event = 0;
/**
* 列数
*/
int col = 0;
/**
* 颜色
*/
int[] val;
/**
* 特殊块类型
*/
int type;
public Block(int[] val){
this.val = val;
}
public Block(int event,int type){
this.event = event;
this.type = type;
}
}
package tetris;
/**
* @Author jinjun99
* @Date Created in 2021/11/22 17:23
* @Description
* @Since version-1.0
*/
public class Point {
int x = 0;
int y = 0;
public Point(int x, int y) {
this.x = x;
this.y = y;
}
public Point(){
}
}
package tetris;
import java.util.Stack;
/**
* @Author jinjun99
* @Date Created in 2021/11/22 16:44
* @Description
* @Since version-1.0
*/
public class Demo02 {
private static int width = 5;
private static int height = 10;
private static int[][] map = new int[width][height];
private static int[][] mark1 = new int[width][height];
private static int[][] mark2 = new int[width][height];
private static Block block;
private static int[] tail = new int[height];
private static Point[] drop = new Point[width*height];
/**
* 跑马灯移动数组
* @param num 移动位数
*/
private static void rotate(int num){
if (num == 1){
int temp = 0;
temp = block.val[0];
block.val[0] = block.val[2];
block.val[2] = block.val[1];
block.val[1] = temp;
}
if (num == 2){
int temp = 0;
temp = block.val[0];
block.val[0] = block.val[1];
block.val[1] = block.val[2];
block.val[2] = temp;
}
}
/**
* 移动
* @param distance
*/
private static void move(int distance){
block.col+=distance;
if (block.col>=width){
block.col=width-1;
}
if (block.col<0){
block.col=0;
}
}
/**
* 块落地后的坐标
* @param args
*/
private static void simpleLand(){
if (block.event==0){
drop[0]=new Point(block.col,tail[block.col]++);
drop[1]=new Point(block.col,tail[block.col]++);
drop[2]=new Point(block.col,tail[block.col]++);
map[drop[0].x][drop[0].y] = block.val[2];
map[drop[1].x][drop[1].y] = block.val[1];
map[drop[2].x][drop[2].y] = block.val[0];
// int dropNum = 3;
solution(3);
}
}
private static void solution(int dropNum){
while (dropNum!=0){
for (int i = 0; i < dropNum; i++) {
if (map[drop[i].x][drop[i].y]==0){
continue;
}
dfs1(drop[i].x,drop[i].y);
clear();
}
dropNum = updateMap();
}
}
private static int[] dirX = {0,1,1,1,0,-1,-1,-1};
private static int[] dirY = {1,1,0,-1,-1,-1,0,1};
/**
* 消除点集
*/
private static Stack<Point> eliminate = new Stack<>();
/**
*
* @param x
* @param y
*/
private static void dfs1(int x, int y){
Stack<Point> temp = new Stack<>();
if (map[x][y]!=0){
for (int i = 0; i < 4; i++) {
int l = i;
int k = 0;
int a = x;
int b = y;
while (k!=2){
a+=dirX[l];
b+=dirY[l];
if (a>=0&&b>=0&&a<width&&b<height&&map[x][y]==map[a][b]&& mark1[a][b]==0){
mark1[a][b]=1;
temp.push(new Point(a,b));
}else {
k++;
l+=4;
a=x;
b=y;
}
}
int s = temp.size();
if (s>=2&& mark1[x][y]==0){
mark1[x][y]=1;
eliminate.push(new Point(x,y));
}
for (int j = 0; j < s; j++) {
Point p = temp.pop();
if (s>=2){
eliminate.push(p);
dfs1(p.x,p.y);
}
//回溯
mark1[p.x][p.y]=0;
}
}
mark1[x][y]=0;
}
}
private static void specialLand(){
int x = block.col;
int y = tail[block.col]-1;
if (block.type==1){
int color = map[x][y];
for (int i = 0; i < width; i++) {
int h = tail[i];
for (int j = 0; j < h; j++) {
if (map[i][j]==color){
map[i][j]=0;
tail[i]--;
}
}
}
}
if (block.type==2){
dfs2(x,y);
clear();
}
int d = updateMap();
solution(d);
}
private static void dfs2(int x,int y){
eliminate.push(new Point(x,y));
mark2[x][y]=1;
for (int i = 0; i < 8; i++) {
int a = x+dirX[i];
int b = y+dirY[i];
if (a>=0&&b>=0&&a<width&&b<height&&map[a][b]==map[x][y]&& mark2[a][b]==0){
dfs2(a,b);
}
}
}
/**
* 根据搜索结果清理同色块
*/
private static void clear(){
int s = eliminate.size();
for (int i = 0; i < s; i++) {
Point p = eliminate.pop();
// System.out.println("clear:map["+p.x+"]["+p.y+"] ");
if (map[p.x][p.y]!=0){
map[p.x][p.y]=0;
tail[p.x]--;
}
}
mark1 = new int[width][height];
mark2 = new int[width][height];
eliminate.removeAllElements();
}
/**
* 更新块下落后的地图
*/
private static int updateMap(){
//下落数组下标，把所有下落的块按顺序放入下落数组
int a = 0;
//记录下落块数
int sum = 0;
for (int i = 0; i < width; i++) {
for (int j = 0; j < tail[i]; j++) {
if (map[i][j]==0){
//下落高度
int h = 1;
while (map[i][j+h]==0&&j+h<height){
h++;
}
map[i][j] = map[i][j + h];
map[i][j + h] = 0;
drop[a++] = new Point(i, j);
sum++;
}
}
}
return sum;
}
private static void newSimpleBlock(int a, int b, int c){
block = new Block(new int[]{a,b,c});
}
private static void newSpecialBlock(int type){
block = new Block(1,type);
}
public static void main(String[] args) {
newSimpleBlock(1,3,2);
move(0);
simpleLand();
newSimpleBlock(3,4,2);
move(1);
simpleLand();
newSimpleBlock(2,5,3);
move(3);
simpleLand();
newSimpleBlock(5,3,2);
move(2);
simpleLand();
newSimpleBlock(2,5,2);
move(4);
simpleLand();
newSpecialBlock(2);
move(3);
specialLand();
newSimpleBlock(1,2,1);
move(2);
simpleLand();
newSpecialBlock(1);
specialLand();
for (int i = height-1; i >= 0; i--) {
for (int j = 0; j < width; j++) {
System.out.print(" "+map[j][i]+" ");
if (j== width -1){
System.out.println();
}
}
}
}
}
打印过程：
0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 1 0 0 0 0 3 0 0 0 0 2 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 1 3 0 0 0 3 4 0 0 0 2 2 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 1 3 0 2 0 3 4 0 5 0 2 2 0 3 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 1 0 0 2 0 3 4 5 5 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 2 1 0 0 2 5 3 4 5 5 2 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 1 0 0 0 0 3 4 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 1 0 0 1 0 2 0 0 3 4 1 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 3 4 2 0 0
这篇关于Tetris DFS算法练习的文章就介绍到这儿，希望我们推荐的文章对大家有所帮助，也希望大家多多支持为之网！
您可能喜欢
-
项目：远程温湿度检测系统12-22
-
《鸿蒙HarmonyOS应用开发从入门到精通（第2版）》简介12-21
-
后台管理系统开发教程：新手入门全指南12-21
-
后台开发教程：新手入门及实战指南12-21
-
后台综合解决方案教程：新手入门指南12-21
-
接口模块封装教程：新手必备指南12-21
-
请求动作封装教程：新手必看指南12-21
-
RBAC的权限教程：从入门到实践12-21
-
登录鉴权实战：新手入门教程12-21
-
动态权限实战入门指南12-21
-
功能权限实战：新手入门指南12-21
-
后台管理开发项目实战：从入门到独立开发12-21
-
后台管理系统开发项目实战：新手入门教程12-21
-
后台开发项目实战：新手入门教程12-21
-
后台综合解决方案项目实战：新手入门教程12-21
栏目导航
