干支纪年法属于上古以来中国纪年历法,其由十天干十二地支按照一定顺序结合来表示年份.

十天干分别为:

甲、乙、丙、丁、戊、己、庚、辛、壬、癸

十二地支分别为:

子、丑、寅、卯、辰、巳、午、未、申、酉、戌、亥

干支纪年基本规则:

 甲子、乙丑......癸酉对应结束后此时应当对应甲戊,乙亥,丙子.........

以此类推,所以干支纪年法六十年一轮回.

当我们想要用循环输出一个轮回的干支纪年法的时候,基本思路如下:

1、创建两个数组分存放天干地支

2、使用for循环依次输出对应天干地支

代码如下:

public class practice {
    public static void main(String[] args) {
        String sky[] = {"甲","乙","丙","丁","戊","己","庚","辛","壬","癸"};
        String land[] = {"子","丑","寅","卯","辰","巳","午","未","申","酉","戌","亥"};
        String[] array = new String[60];
        int j = 0;
        int freq = 0;
        int k=0;
        while(freq < 60){   //打印六十次
            for(int i = 0;i < 10;i++){     //十天干
                if(j == 12){          //十二地支,由于数组下标从0开始,所以当地支等于十二时归零
                    j = 0;
                }
                System.out.print(" "+sky[i]+land[j]+"年");
                k++;
                if(k==12){  //为方便检查,一行打印十二次后回车
                    System.out.println();
                    k=0;
                }
                freq++;   //打印次数
                j++;
            }
        }
    }

结果如下:

特别注意的是当地支到11时就需要归零,否则打印时就会访问越界

下面看下如何输入一个年份判断其是什么年:

判断方法:

天干:用年份减3除10,取余数(余数1,2,3,4,5......9,0,分别对应甲,乙,丙,丁......癸)

地支:用年份减3除12,取余数(余数1,2,3,4,5......11,0,分别对应子,丑,寅,卯......亥)

代码如下:

import java.util.Scanner;

public class practice {
    public static void main(String[] args) {
        String sky[] = {"甲", "乙", "丙", "丁", "戊", "己", "庚", "辛", "壬", "癸"};
        String land[] = {"子", "丑", "寅", "卯", "辰", "巳", "午", "未", "申", "酉", "戌", "亥"};
        Scanner scanner = new Scanner(System.in);
        System.out.print("请输入年份:");
        int input = scanner.nextInt();
        int i = (input - 3) % 10;   //计算天干
        int j = (input - 3) % 12;   //计算地支
        if (i == 0) {
            i = 10;      //余数为0对应天干最后一个
        }
        if (j == 0) {
            j = 12;      //余数为0对应地支最后一个
        }
            System.out.println(input + "是" + sky[i - 1] + land[j - 1] + "年");
    }
}

结果: