本文主要是介绍二分查找及各种变体实现,对大家解决编程问题具有一定的参考价值,需要的程序猿们随着小编来一起学习吧!
public class BinarySearch {
// 二分查找
public static int bSearch(int[] nums, int target) {
int n = nums.length;
int low = 0;
int high = n - 1;
while (low <= high) {
int mid = low + ((high - low) >> 1);
if (nums[mid] > target) {
high = mid - 1;
} else if (nums[mid] < target) {
low = mid + 1;
} else {
return mid;
}
}
return -1;
}
// 查找第一个值等于给定值的元素
public static int searchFirstTarget(int[] nums, int target) {
int n = nums.length;
int low = 0;
int high = n - 1;
while (low <= high) {
int mid = low + ((high - low) >> 1);
if (nums[mid] > target) {
high = mid - 1;
} else if (nums[mid] < target) {
low = mid + 1;
} else {
if (mid == 0 || nums[mid - 1] != target) {
return mid;
} else {
high = mid - 1;
}
}
}
return -1;
}
// 查找最后一个值等于给定值的元素
public static int searchLastTarget(int[] nums, int target) {
int n = nums.length;
int low = 0;
int high = n - 1;
while (low <= high) {
int mid = low + ((high - low) >> 1);
if (nums[mid] > target) {
high = mid - 1;
} else if (nums[mid] < target) {
low = mid + 1;
} else {
if (mid == n - 1 || nums[mid + 1] != target) {
return mid;
} else {
low = mid + 1;
}
}
}
return -1;
}
// 查找第一个大于等于给定值的元素
public static int searchFirstGreaterOrEqual2Target(int[] nums, int target) {
int n = nums.length;
int low = 0;
int high = n - 1;
while (low <= high) {
int mid = low + ((high - low) >> 1);
if (nums[mid] >= target) {
if (mid == 0 || nums[mid - 1] < target) {
return mid;
} else {
high = mid - 1;
}
} else {
low = mid + 1;
}
}
return -1;
}
// 查找第一个小于等于给定值的元素
public static int searchLastLessOrEqual2Target(int[] nums, int target) {
int n = nums.length;
int low = 0;
int high = n - 1;
while (low <= high) {
int mid = low + ((high - low) >> 1);
if (nums[mid] <= target) {
if (mid == n - 1 || nums[mid + 1] > target) {
return mid;
} else {
low = mid + 1;
}
} else {
high = mid - 1;
}
}
return -1;
}
// 查找元素的第一个和最后一个位置
public static int[] searchRange(int[] nums, int target) {
int n = nums.length;
int low = 0;
int high = n - 1;
int[] ans = new int[]{-1, -1};
while (low <= high) {
int mid = low + ((high - low) >> 1);
if (nums[mid] < target) {
low = mid + 1;
} else if (nums[mid] > target) {
high = mid - 1;
} else {
int start = mid;
int end = mid;
while (start >= 0 && nums[start] == target) {
start--;
}
while (end <= n - 1 && nums[end] == target) {
end++;
}
ans[0] = start + 1;
ans[1] = end - 1;
return ans;
}
}
return ans;
}
}
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