本文主要是介绍05-Pandas层级索引,对大家解决编程问题具有一定的参考价值,需要的程序猿们随着小编来一起学习吧!
1.层级索引
import numpy as np
import pandas as pd
s1 = pd.Series(np.random.randn(12),index = [['a','a','a','b','b','b','c','c','c','d','d','d'],[0,1,2,0,1,2,0,1,2,0,1,2]])
s1
a 0 1.766538
1 0.345160
2 -1.049204
b 0 -0.212596
1 0.220403
2 -1.001067
c 0 -0.471350
1 0.823931
2 -0.551105
d 0 -0.190322
1 0.701434
2 -0.571929
dtype: float64
print(type(s1.index))
print(s1.index)
<class 'pandas.core.indexes.multi.MultiIndex'>
MultiIndex([('a', 0),
('a', 1),
('a', 2),
('b', 0),
('b', 1),
('b', 2),
('c', 0),
('c', 1),
('c', 2),
('d', 0),
('d', 1),
('d', 2)],
)
2.选取
#1.外层选取
s1['b']
0 -0.212596
1 0.220403
2 -1.001067
dtype: float64
#2.内层获取
s1[:,2]
a -1.049204
b -1.001067
c -0.551105
d -0.571929
dtype: float64
s1['a',0]
1.766537562273998
3.交换
#1.swaplevel()交换内层和外层的索引
s1.swaplevel()
0 a 1.766538
1 a 0.345160
2 a -1.049204
0 b -0.212596
1 b 0.220403
2 b -1.001067
0 c -0.471350
1 c 0.823931
2 c -0.551105
0 d -0.190322
1 d 0.701434
2 d -0.571929
dtype: float64
#2.sortlevel()先对外层索引进行排序,在对内层索引进行排序, 默认升序
s1.sortlevel() # 此方法现在好像不支持了,需要使用 sort_index()方法,
D:\Anaconda\lib\site-packages\ipykernel_launcher.py:2: FutureWarning: sortlevel is deprecated, use sort_index(level=...)
a 0 -0.241259
1 0.898846
2 -0.233832
b 0 0.796350
1 0.025104
2 1.232659
c 0 -0.899175
1 0.684583
2 0.970989
d 0 -0.075916
1 -1.913964
2 0.223474
dtype: float64
#交换并排序分层
s1.swaplevel().sortlevel() # 这个也是不行了
---------------------------------------------------------------------------
AttributeError Traceback (most recent call last)
<ipython-input-11-413a6bd8d6a7> in <module>
1 #交换并排序分层
----> 2 s1.swaplevel().sortlevel()
d:\python\lib\site-packages\pandas\core\generic.py in __getattr__(self, name)
5139 if self._info_axis._can_hold_identifiers_and_holds_name(name):
5140 return self[name]
-> 5141 return object.__getattribute__(self, name)
5142
5143 def __setattr__(self, name: str, value) -> None:
AttributeError: 'Series' object has no attribute 'sortlevel'
这篇关于05-Pandas层级索引的文章就介绍到这儿,希望我们推荐的文章对大家有所帮助,也希望大家多多支持为之网!