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念整数的两种c程序

本文主要是介绍念整数的两种c程序,对大家解决编程问题具有一定的参考价值,需要的程序猿们随着小编来一起学习吧!
#include <stdio.h>
int main()
{  
    int x;
    int mask=1;                          //用来判断位数 
    do{
	    scanf("%d",&x);
}while(x>100000||x<-100000);             //判断是否在输入范围内 
    if(x<0){
    	printf("fu ");
    	x=-x;
	}                                    //正负 
    int b=x;                             //暂时寄存x 
    while(b>9){
    	b/=10;
    	mask*=10;                        //比如x=123 要循环两次 mask就为100,后面这个while循环就结束了,接着x=23,mask=10,x=3,mask=1
	}
	int a;
	while(mask>0)
	{
		a=x/mask;                         //用来分解x 
		x%=mask;                           
		mask/=10;
		switch (a){
			case 0:
				printf("ling");
				break;
			case 1:
				printf("yi");
				break;
			case 2:
				printf("er");
				break;
			case 3:
				printf("san");
				break;
			case 4:
				printf("si");
				break;
			case 5:
				printf("wu");
				break;
			case 6:
				printf("liu");
			    break;
			case 7:
				printf("qi");
				break;
			case 8:
				printf("ba");
				break;
			case 9:
				printf("jiu");
				break;
		}
	        if(mask>0)
			printf(" ");                         //最后一位数后面不输出空格 
	}
return 0;
}

#include <stdio.h>
int main()
{
    int number;
    scanf("%d", &number);//123 
    if (number < 0)
    {
        printf("fu ");
        number = -number;
    }

    int temp = number;//123
    int cnt = 1;
    while (temp > 9)
    {
        temp /= 10;//12            1
        cnt *= 10;   //10       10
    } 

    while ( cnt > 0)
    {
        int i;                //12
        i = number / cnt; //12     1
        switch (i)
        {
            case 0:
                printf("ling");
                break;
            case 1:
                printf("yi");
                break;
            case 2:
                printf("er");
                break;
            case 3:
                printf("san");
                break;
            case 4:
                printf("si");
                break;
            case 5:
                printf("wu");
                break;
            case 6:
                printf("liu");
                break;
            case 7:
                printf("qi");
                break;
            case 8:
                printf("ba");
                break;
            case 9:
                printf("jiu");
                break;          
        }
        number %= cnt;//3  
        cnt /= 10;//1 1
        if (cnt > 0)
        {
            printf(" ");
        }
        
    }
        
    return 0;
}




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