稀疏数组的处理方式是:
如下图:左边是原始数组,右边是稀疏数组
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public class ArrayLearing08 { public static void main(String[] args) { //1.创建一个二维数组11*11 0:没有棋子, 1:黑棋 2:白棋 int[][] array1 = new int[11][11]; array1[1][2] = 1; array1[2][3] = 2; //输出原始的数组 System.out.println("输出原始的数组"); for (int[] ints : array1) { for (int anInt : ints) { System.out.print(anInt+"\t"); } System.out.println(); } System.out.println("============================"); //转换成稀疏数组保存 //获取有效值的个数 int sum = 0; for (int i = 0; i < 11; i++) { for (int j = 0; j < 11; j++) { if (array1[i][j]!=0){ sum++; } } } System.out.println("有效的的个数:"+sum); //2.创建一个稀疏数组的数组 int[][] array2 = new int[sum+1][3]; array2[0][0] = 11; array2[0][1] = 11; array2[0][2] = sum; //便利二维数组,将非零的值,存放稀疏数组中 int count = 0; for (int i = 0; i < array1.length; i++) { for (int j = 0; j < array1[i].length; j++) { if (array1[i][j]!=0){ count++; array2[count][0] = i; array2[count][1] = j; array2[count][2] = array1[i][j]; } } } //输出稀疏数组 System.out.println("稀疏数组"); for (int i = 0; i < array2.length; i++) { System.out.println(array2[i][0]+"\t" +array2[i][1]+"\t" +array2[i][2]+"\t"); } } } System.out.println("============================"); System.out.println("还原"); //1.读取稀疏数组 int[][] array3 = new int[array2[0][0]][array2[0][1]]; //2.给其中的元素还原它的值 for (int i = 1; i < array2.length; i++) { array3[array2[i][0]][array2[i][1]] = array2[i][2]; } //3.打印 System.out.println("输出还原的数组"); for (int[] ints : array3) { for (int anInt : ints) { System.out.print(anInt+"\t"); } System.out.println(); } } }
nt(anInt+"\t");
}
System.out.println();
}
}
}