本文主要是介绍马拉车算法寻找字符串最大回文串,对大家解决编程问题具有一定的参考价值,需要的程序猿们随着小编来一起学习吧!
#include <iostream>
#include <string>
using namespace std;
class Solution {
public:
int getLongestPalindrome(string A, int n) {
// write code here
char* s2 = (char*)malloc(2 * n + 1);
int* tempLen = (int*)malloc((2 * n + 1) * 4);
//int tempLen[219*2+1] = { 0 };
for (int i = 0; i < (2 * n + 1); i++) {
if (i % 2) {
s2[i] = A[i / 2];
}
else {
s2[i] = '#';
}
tempLen[i] = 0;
}
int curMaxRightIndex = 0; //现有字符回文能到达的最右边索引
int centerIndexOfCurMaxRightIndex = 0; //到达最右边索引的中心索引值
int maxLen = 0; //最大回文半径,非原始字符串
for (int i = 0; i < (2 * n + 1); i++) {
if (i < curMaxRightIndex ) {
tempLen[i] = min(tempLen[2 * centerIndexOfCurMaxRightIndex - i], curMaxRightIndex - i);
}
else {
tempLen[i] = 1;
}
for (; (i - tempLen[i] >= 0) && (i + tempLen[i] < 2 * n + 1) && (s2[i - tempLen[i]] == s2[i + tempLen[i]]); tempLen[i]++);
if (i + tempLen[i] > curMaxRightIndex) {
curMaxRightIndex = i + tempLen[i];
centerIndexOfCurMaxRightIndex = i;
}
if (maxLen <= tempLen[i]) {
maxLen = tempLen[i];
}
}
return maxLen - 1;
}
};
int main() {
string s("dbadddadbbaabbcbcddbabacbdccdcbaddccdaacdccbcdaadadccbdbabddaaddbddbdaddbaadbabcaabccbacaacdaddbaadbadbbccababaaccbbbcccbbdbbdacbcaacaddccbbdbbbdacdbbdccaaddcdbadabdcbabcabbccdbdabbbaabacabababcbbcdcdcbbdcdcadbcaadaddcb");
cout << sizeof(int) << endl;
Solution so;
int len = 0;
len = so.getLongestPalindrome(s, 219);
cout << len << endl;
return 0;
}
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