python中,字典还是一些列的键-值对。每个键都与一个值相关联。键是不可变类型也不能重复,值可以是任意类型,可以将任何python对象用作字典中的值。
键值之间用冒号隔开,键值对之间用逗号隔开。在字典中你存储多少个键值对都可以
sample:
dict_sample = {"name": "甲壳虫~~~", "age": "18"}
赋值创建,函数创建
person1_info = {}
person2_info = {"name": "甲壳虫", "age": "18"}
person2_info = {"name": "甲壳虫", "age": 18, "sex": "男", "garde": "七年级", "addr":["中国","江苏省", "南京市"], ""friends": {"name1": "Jack", "name2": "Merry"} }
print(dict([()])) """ | dict() -> new empty dictionary | dict(mapping) -> new dictionary initialized from a mapping object's | (key, value) pairs | dict(iterable) -> new dictionary initialized as if via: | d = {} | for k, v in iterable: | d[k] = v | dict(**kwargs) -> new dictionary initialized with the name=value pairs | in the keyword argument list. For example: dict(one=1, two=2) 下面还有很多。。。仅仅截取这些 """
print(dict()) #{}
#(iterable,可迭代对象) cattle = [("name", "甲壳虫~~~"), ("age", 18), ("sex", "男")] print(dict(cattle))#{'name': '甲壳虫~~~', 'age': 18, 'sex': '男'} peach = [["name", "桃子"], ["age", 16], ["sex", "女"]] print(dict(peach))#{'name': '桃子', 'age': 16, 'sex': '女'}
1 baby = dict(name="Little Baby", sex="男") 2 print(baby, '~~~', type(baby))#{'name': 'Little Baby', 'sex': '男'} ~~~ <class 'dict'>
zip_data = zip(("name", "age", "sex"), ("peach", 16, "girl")) print(dict(zip_data))#{'name': 'peach', 'age': 16, 'sex': 'girl'}
字典是键值对形式存在字典中。键和值是一种映射关系。
获取字典中的,值,键和值;
dic = {"name": "甲壳虫", "age": 18} print(dic['name'])#甲壳虫 print(dic["sex"])#KeyError: 'sex'
dic = {"name": "甲壳虫", "age": 18} dic['sex'] = '男' print(dic)#{'name': '甲壳虫', 'age': 18, 'sex': '男'}
dic = {"name": "甲壳虫", "age": 18} dic['sex'] = '男' del dic["age"] print(dic)#{'name': '甲壳虫', 'sex': '男'}
dic = {"name": "甲壳虫", "age": 18} dic['sex'] = '女' print(dic)#{'name': '甲壳虫', 'age': 18, 'sex': '女'}
dic = {"name": "甲壳虫", "age": 18} key_in = "name" in dic print(key_in)#True key_not_in = 'sex' in dic print(key_not_in)#False
dic = {"name": "甲壳虫", "age": 18} value_in = "甲壳虫" in dic["name"] print(value_in)
其实还是根据键,获取到对应的值,然后在去测试是否在字典中(in , not in )
字典的方法-->字典也是一个类
dic = {"name": "甲壳虫", "age": 18} """ D.clear() -> None. Remove all items from D. """ a = dic.clear() print(a)#None
dic = {"name": "甲壳虫", "age": 18} """ Return the value for key if key is in the dictionary, else default.None""" print(dic.get("name", "这个默认值是否返回"))#甲壳虫 print(dic.get("sex", "键不在字典中,这里返回了此处设置的默认值"))#键不在字典中,这里返回了此处设置的默认值
dic = {"name": "甲壳虫", "age": 18} """ D.update([E, ]**F) -> None. Update D from dict/iterable E and F. If E is present and has a .keys() method, then does: for k in E: D[k] = E[k] If E is present and lacks a .keys() method, then does: for k, v in E: D[k] = v In either case, this is followed by: for k in F: D[k] = F[k]""" dic.update({"name": "peach"})#键存在 更新键所对应的值 print(dic)#{'name': 'peach', 'age': 18} dic.update({"friend": "peach"})#不键存在 ,添加新的键值对 print(dic)#{'name': 'peach', 'age': 18, 'friend': 'peach'}
1 dic = {"name": "甲壳虫", "age": 18} 2 """ Insert key with a value of default if key is not in the dictionary. 3 Return the value for key if key is in the dictionary, else default. 4 None""" 5 """如果键不在字典中,向字典中添加对应的键值对;并返回默认值 6 如果键在字典中,直接返回默认的值 7 """ 8 print(dic.setdefault("age", None))#键在字典中,返回键所对应的值 9 print(dic)#{'name': '甲壳虫', 'age': 18} 10 print(dic.setdefault("friend", "键不在字典中"))#键不在字典中,返回设置的值:键不在字典中 11 print(dic)#字典中添加了新的键值对{'name': '甲壳虫', 'age': 18, 'friend': '键不在字典中'}
dic = {"name": "甲壳虫", "age": 18} """ D.pop(k[,d]) -> v, remove specified key and return the corresponding value. If key is not found, default is returned if given, otherwise KeyError is raised None""" print(dic.pop("name"))#甲壳虫 print(dic)#{'age': 18}
dic = {"name": "甲壳虫", "age": 18} """ D.pop(k[,d]) -> v, remove specified key and return the corresponding value. If key is not found, default is returned if given, otherwise KeyError is raised None""" print(dic.popitem())#('age', 18) print(dic)#{'name': '甲壳虫'}
"""fromkeys(iterable, value=None, /) method of builtins.type instance Create a new dictionary with keys from iterable and values set to value. None""" lst = ["name-1", "name-2"] dict_tester = dict(dict.fromkeys(lst)) print(dict_tester)#{'name-1': None, 'name-2': None} tup = ("name-1", "name-2") print(dict.fromkeys(tup))#{'name-1': None, 'name-2': None} print(dict.fromkeys(["name-1", "name-2", "姓名"]))#{'name-1': None, 'name-2': None, '姓名': None}