Input Specification:
Each input file contains one test case which gives three numbers N, A and B, where N (<100) is the number of significant digits, and A and B are the two float numbers to be compared. Each float number is non-negative, no greater than 10100, and that its total digit number is less than 100.
Output Specification:
For each test case, print in a line YES if the two numbers are treated equal, and then the number in the standard form 0.d[1]...d[N]*10k (d[1]>0 unless the number is 0); or NO if they are not treated equal, and then the two numbers in their standard form. All the terms must be separated by a space, with no extra space at the end of a line.
Note: Simple chopping is assumed without rounding.
Sample Input 1:
3 12300 12358.9
结尾无空行
Sample Output 1:
YES 0.123*10^5
结尾无空行
Sample Input 2:
3 120 128
结尾无空行
Sample Output 2:
NO 0.12010^3 0.12810^3
结尾无空行
代码:
#include <iostream> #include <string> using namespace std; int n; //有效位 string func(string s,int &e){ int k = 0; while(int(s.length()) > 0 && s[0] == '0'){ s.erase(s.begin()); //去掉前导的0 } if(s[0] == '.'){ //去掉前导0后是小数点,说明这个数是小数 s.erase(s.begin()); while(int(s.length()) > 0 && s[0] == '0'){ s.erase(s.begin()); //去掉小数点后不是零位置前的所有零 e--; } }else{ //去掉前导零后不是小数点,则找到后面的小数点删除 while(k < int(s.length()) && s[k] != '.'){ k++; e++; //只要没遇到小数点就让指数e加一 } if(k < int(s.length())){ //while结束后k < s.length(),说明遇到小数点 s.erase(s.begin() + k); //删除小数点 } if(int(s.length()) == 0){ e = 0; //如果去除前导零后s的长度变为0,那么说明这个数就是0 } } int num = 0; k = 0; string res; while(num < n){ if(k < int(s.length())) res += s[k++]; else res += '0'; num++; //精度加1 } return res; } int main(){ string s1,s2,s3,s4; cin >> n >> s1 >> s2; int e1 = 0,e2 = 0; s3 = func(s1,e1); s4 = func(s2,e2); if(s3 == s4 && e1 == e2){ cout << "YES 0." << s3 << "*10^"<< e1 << endl; }else{ cout << "NO 0." << s3 << "*10^" << e1 << " 0." << s4 << "*10^" << e2 << endl; } return 0; }
提交结果截图:
问题:
1.结果出现一个答案错误,但不清楚其测试用例是什么?
2.warning: comparison between signed and unsigned integer expressions [-wsign-compare]
避免使用无符号数,其中使用了s.length(),返回的值应该是一个unsigned int,所以导致出现这个错误,因此在使用其进行比较的时候,需改为int(s.length())。
3.我不知道为什么这个markdown格式中只有105显示不成功!??