https://www.jb51.net/article/87237.htm
memset 是重置
memcopy(b,a,n*sizeof(int))
a拷贝到b
#include<iostream> #include<algorithm> #include<string.h> using namespace std; int main(){ int i=1;int n,q,t; while(cin>>n>>q){ //卡牌张数,问题数 int card[n]; for(int k=0;k<n;k++){ cin>>card[k]; } int cards[n]; memcpy(cards, card, n*sizeof(int)); //card赋值给cards cout<<"Case #"<<i<<":"<<endl; sort(cards,cards+n); while(q--){ cin>>t; int ix1=-1,ix2=-1; for(int m=0;m<n;m++){ //ix1 if(card[m]==t){ ix1=m+1;break;} } for(int m=0;m<n;m++){ //ix2 if(cards[m]==t){ ix2=m+1;break;} } if(ix1!=-1){ cout<<t<<" from "<<ix1<<" to "<<ix2<<endl; }else{ cout<<t<<" not found"<<endl; } } i++; } }