Java教程

sqlilabs(SQL注入)小白通基础通关笔记(专针对小白)(第六关Less-6)

本文主要是介绍sqlilabs(SQL注入)小白通基础通关笔记(专针对小白)(第六关Less-6),对大家解决编程问题具有一定的参考价值,需要的程序猿们随着小编来一起学习吧!
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>Less-6 Double Query- Double Quotes- String</title>
</head>

<body bgcolor="#000000">
<div style=" margin-top:60px;color:#FFF; font-size:23px; text-align:center">Welcome&nbsp;&nbsp;&nbsp;<font color="#FF0000"> Dhakkan </font><br>
<font size="3" color="#FFFF00">


<?php
//including the Mysql connect parameters.
include("../sql-connections/sql-connect.php");
error_reporting(0);
// take the variables
if(isset($_GET['id']))
{
$id=$_GET['id'];
//logging the connection parameters to a file for analysis.
$fp=fopen('result.txt','a');
fwrite($fp,'ID:'.$id."\n");
fclose($fp);

// connectivity 

$id = '"'.$id.'"';
$sql="SELECT * FROM users WHERE id=$id LIMIT 0,1";
//这个和第四关相似,so我这里就简单一讲。
//http://127.0.0.1/sqli-labs/Less-4/?id=-1" union select 1,2,3 --+
//加工后:"-1" union select 1,2,3 --+"
//sql语句相当于:SELECT * FROM users WHERE id="-1" union select 1,2,3 
$result=mysql_query($sql);
$row = mysql_fetch_array($result);

	if($row)
	{
  	echo '<font size="5" color="#FFFF00">';	
  	echo 'You are in...........';
  	echo "<br>";
  	echo "</font>";
  	}
	else 
	{
	
	echo '<font size="3"  color= "#FFFF00">';
	print_r(mysql_error());
	echo "</br></font>";	
	echo '<font color= "#0000ff" font size= 3>';	
	
	}
}
	else { echo "Please input the ID as parameter with numeric value";}

?>
</font> </div></br></br></br><center>
<img src="../images/Less-6.jpg" /></center>
</body>
</html>

这篇关于sqlilabs(SQL注入)小白通基础通关笔记(专针对小白)(第六关Less-6)的文章就介绍到这儿,希望我们推荐的文章对大家有所帮助,也希望大家多多支持为之网!