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Leetcode 1333. Filter Restaurants by Vegan-Friendly, Price and Distance [Python]

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list.sort(key = lambda x: (x[0], x[1]。。。))的用法可以快速解决问题，

class Solution:
    def filterRestaurants(self, restaurants: List[List[int]], veganFriendly: int, maxPrice: int, maxDistance: int) -> List[int]:
        cand = []
        if veganFriendly == 1:
            for idx, rest in enumerate(restaurants):
                if rest[2] == veganFriendly and rest[3] <= maxPrice and rest[4] <= maxDistance:
                    cand.append(rest)
        else:
            for idx, rest in enumerate(restaurants):
                if rest[3] <= maxPrice and rest[4] <= maxDistance:
                    cand.append(rest)
        
        cand.sort(key = lambda x:(x[1], x[0]), reverse = True)
        res = []
        for can in cand:
            res.append(can[0])
        return res

不过面试里没准要自己写比较器之类的吧。题目里的餐厅ID不全是1、2、3。。。算是一个坑？。。

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